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OT: Converting y = Ae^bx to base 10

Posted By: Jason Lee
Date: Sunday, 29 January 2012, at 3:48 p.m.

In Response To: OT: Converting y = Ae^bx to base 10 (Casper van der Tak)

Let me give you the why... you've got the equation e^bx = 10^cx and you are trying to solve for c.

e^(bx) = 10^(cx)

Take the base 10 log of both sides: log10(e^(bx)) = cx

Use a log of exponents/logs: bx log10(e) = cx

Solve for c: b log10(e) = c

JLee

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