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New standard method for resolving 3-way ties on the ABT

Posted By: Sean Garber
Date: Monday, 2 July 2018, at 4:21 a.m.

In Response To: New standard method for resolving 3-way ties on the ABT (TarHeelFan)

Let us name the two 10-2 players playing each other Player "A" and Player "B". Let us call the 10-2 player playing the 9-3 player Player "C". The Player "A"/Player "B" winner may win the tournament with an 11-2 record if Player "C" loses this round. Player "C" will always have to go 12-2 to win the tournament. "A" and "B" each have a 37.5% chance to win the tournament, while Player "C" has 25%. Player "A" and Player "B" have each received half a bye with the round 13 draw. What could make the situation worse: Player "A" may have already gotten a bye in an earlier round. Player "A" could win the tournament with a real record of 10-2, while Player "C" would have to go 12-2 to win in all situations.

Don't get me wrong. I enjoy playing in a Swiss system tournament. Some seem to think that a Swiss is a panacea of fairness. It is imperfect, just like all other systems. The unfairness in a Swiss is simply hidden better than the unfairness in a bracketed tournament.

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