[ View Thread ] [ Post Response ] [ Return to Index ] [ Read Prev Msg ] [ Read Next Msg ]

BGonline.org Forums

a probabilities question - correction

Posted By: bluedice
Date: Monday, 2 July 2018, at 7:43 a.m.

In Response To: a probabilities question - correction (Mike Clapsadle)

Agreed...

Excluding first rolls.

Assuming dice rolls are perfectly distributed.

(A)

First pick, P(doublet) = 1/6

Second pick P(Matching doublet) = 1/6 x 1/36 = 1/216

OR

(B)

First pick, P(non doublet) = 5/6

Second pick P(Matching non doublet, 62 = 26) = 5/6 x 1/18 = 5/108

Solution:

P(A) + P(B) = 1/216 + 5/108 = 0.051 (5.1%)

Messages In This Thread

 

Post Response

Your Name:
Your E-Mail Address:
Subject:
Message:

If necessary, enter your password below:

Password:

 

 

[ View Thread ] [ Post Response ] [ Return to Index ] [ Read Prev Msg ] [ Read Next Msg ]

BGonline.org Forums is maintained by Stick with WebBBS 5.12.