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BGonline.org Forums
a probabilities question - correction
Posted By: bluedice In Response To: a probabilities question - correction (Mike Clapsadle)
Date: Monday, 2 July 2018, at 7:43 a.m.
Agreed...
Excluding first rolls.
Assuming dice rolls are perfectly distributed.
(A)
First pick, P(doublet) = 1/6
Second pick P(Matching doublet) = 1/6 x 1/36 = 1/216
OR
(B)
First pick, P(non doublet) = 5/6
Second pick P(Matching non doublet, 62 = 26) = 5/6 x 1/18 = 5/108
Solution:
P(A) + P(B) = 1/216 + 5/108 = 0.051 (5.1%)
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