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BGonline.org Forums
Naccel 2 -- post #1
Posted By: Nack Ballard In Response To: Naccel 2 -- post #1 (Andreas)
Date: Saturday, 9 January 2010, at 1:14 a.m.
Glad to hear your enthusiasm, Andreas.
The concept of the supis weighted with 0,1,2,3 and the formula: PC= sum of (supi occupation number * weight) + 90
is very clear (supi!! :-) and leads to the exact pipcount.
Right, except that Supi is a female Twi'lek from Star Wars II (Attack of the Clones).
The word you want is "Super" (short for Super-point). There is also "supe" (short for super-pip). They are the same concepts as "point" and "pip," but six times the distance/count.
I hope you don't mind that I change (overwrite) your "supi" to "Super" for the rest of your comments in this post.
(The Super occupation number includes the symmetric distrubuted checker around the Super.)
Right. That's one of the basic ideas.
To whet your appetite, another idea is to group six checkers on or around any point, or three checkers on or around any even-numbered point, or two checkers around any third point, which yield whole counts (no leftover pips).
The question remains, how to handle positions where the checkers are not symmetric distributed around the Supers.
You are not limited to symmetries around the closest Super. For example, reflections around the 0-Super or 2-Super can be nearly 2 supes apart; and easy-to-see mirrored points, which are equidistant from the 1-Super, can be nearly 4 supes (24 pips) apart.
We would have to make a correction +/- c for each Super checker cloud..
The result would be something like:
PC=sum of (Super occupation number * weight) + 90 + sum of corrections
That's right. Except by applying proper technique, you can offset all adjustments but one (or none, a lucky 1/6 of the time).
Nack
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