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n odd

Posted By: Bob Koca
Date: Sunday, 16 May 2010, at 5:33 p.m.

In Response To: Another puzzle/ next question/ SPOILER I hope)_ (Bob Koca)

I suggested before that B can force the game into a position with N (N-1) X's forcing A to lose on his next placement. My strategy for doing that was shown not to work by Nack. I have a modification to it that I think works.

The danger to B is that a position is reached in which there are two lines with n-1 X's with the missing X being in same row or column. e.g.

X X X X *

X X X X *

& & & & &

& & & & &

& & & & &

where * are not filled in and & are possibly filled in.

To avoid this player B must prevent that: Whenever A causes a n-1 and n-2 situation such as

X X X X *

X X X * *

& & & & &

& & & & &

& & & & &

B must "block" by playing in 5th column of row 2. Otherwise B will play by filling in a row column with the fewst number of X's.

Why does this work? I would have to wave my hands too vigorously for someone who is unflappable. If false it shouldn't be too hard to disprove though.

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