Can Anybody Here
Posted By: Bob Koca In Response To: Can Anybody Here (Rich Munitz)
Date: Monday, 10 January 2011, at 7:24 p.m.
In Response To: Can Anybody Here (Rich Munitz)
O.k. I will fix it to suit Rich's objection.
Match to 2^n+1 points. A is winning 2^n to 0 and is holding a 2^n cube in a gin race. As n goes to infinity the differences in the equities goes to 0.
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