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Is this exact?

Posted By: Maik Stiebler
Date: Monday, 30 July 2007, at 11:00 a.m.

In Response To: Is this exact? (Chuck Bower)

I think the problem is that your formula counts any event where more than one player gets many AA during the session as more than one event. Adding up probabilities only works for mutually exclusive events.

I submit P(any player gets five or more AA)=6*(player 1 gets five or more AA)-P(two or more of the players get five or more AA)-P(three or more of theplayers get five or more AA)-..., but I'm not 100% sure that's correct either.

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