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Average number of rolls to roll 66

Posted By: Jason Lee
Date: Friday, 9 September 2011, at 12:39 a.m.

In Response To: Average number of rolls to roll 66 (Bob Koca)

UBK: Here is another way.

Consider what happens on the first roll. If the event occurs then you are done after one trial. If it does not then you have used up one trial and then it is like starting over again. So if E is the expected number of tosses needed and p is the probability of success we have that

E = (p)(1) + (1-p) (1+E)

Solving for E gives E = 1/p.

Consider the following game: A fair coin is flipped until a tail is flipped.

  • If tails appears for the first time on the first flip, you pay me $1.
  • If tails appears for the first time on the second flip, I pay you $2.
  • If tails appears for the first time on the third flip, you pay me $4.
  • If tails appears for the first time on the fourth flip, I pay you $8.
  • ...

How much should I pay to play this game?

JLee

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