Is there a formula for solving this problem? We know that we need to gain half as wins wins as loses gammons. But I was thinking if there is any correlation between the distance of our last checker to our own sixpoint +1 roll and the opponents average number of rolls to bear off(His EPC/8,16)
1. | Rollout1 | 6/1 5/2 | eq: -0,987 |
| Player: Opponent: | 8,62% (G:0,00% B:0,00%) 91,38% (G:19,01% B:0,23%) | Conf.: ± 0,001 (-0,989...-0,986) - [100,0%] Duration: 1 minute 03 seconds |
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2. | Rollout1 | 23/15 | eq: -1,020 (-0,033) |
| Player: Opponent: | 0,00% (G:0,00% B:0,00%) 100,00% (G:1,99% B:0,00%) | Conf.: ± 0,000 (-1,020...-1,020) - [0,0%] Duration: 14,0 seconds |
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3. | Rollout1 | 6/1 4/1 | eq: -1,049 (-0,061) |
| Player: Opponent: | 6,86% (G:0,00% B:0,00%) 93,14% (G:20,95% B:0,30%) | Conf.: ± 0,001 (-1,050...-1,047) - [0,0%] Duration: 1 minute 47 seconds |
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4. | Rollout1 | 23/20 6/1 | eq: -1,057 (-0,069) |
| Player: Opponent: | 2,27% (G:0,00% B:0,00%) 97,73% (G:11,00% B:0,02%) | Conf.: ± 0,001 (-1,057...-1,056) - [0,0%] Duration: 17,6 seconds |
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1 5184 Games rolled with Variance Reduction. Dice Seed: 76008854 Moves: 4-ply, cube decisions: 3-ply
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