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OLM 2013-10-28

Posted By: Taper_Mike
Date: Tuesday, 29 October 2013, at 11:14 a.m.

In Response To: OLM 2013-10-28 (neilkaz)

Ditto for me. If XG does not enter with an ace, we will have solved half our problems, maybe more.

One checker moves into the outer board; one checker moves out. That is the very definition of the Outer family.

O (Outer) = 13/12*/6

Mike

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