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Probability of rolling at least 2 double 6s in 3 rolls
Posted By: Daniel Murphy
Date: Saturday, 10 May 2014, at 5:00 a.m.
In Response To: Probability of rolling at least 2 double 6s in 3 rolls (HOMINID)
It does not matter where the non 66 appears first second or third the sum is the same
True, but as Bob said, 1/36*1/36*35/36 is only the probability of the sequence 66 followed by 66 followed by no 66. There is an equal probability of rolling two other sequences: (1) no 66 followed by 66 followed by 66, and (2) 66 followed by no 66 followed by 66. So you need to multiply 1/36*1/36*35/36 by 3.
your third double six is a red herring
No, because 3 * (1/36*1/36*35/36) is only the probability of rolling exactly two double sixes in three rolls. So you must add another 1/36*1/36*1/36, the probability of rolling exactly 3 double sixes, which also satisfies the original poster's requiresment of "at least" two doubles sixes in three rolls.

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