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Nactation – Algorithm for the Hit Convention
Posted By: Taper_Mike
Date: Thursday, 13 November 2014, at 5:41 a.m.
In Response To: Nactation help (David Rockwell)
White is Player 2
score: 0
pip: 1569 point match pip: 160
score: 1
Blue is Player 1XGID=aECAAfCceB:0:0:1:55:1:0:0:9:10 Blue to play 55
eXtreme Gammon Version: 2.10
43D65R55
Attack Family Rank Traditional Notation Nactation Inside Points Hits Owned Points Blot & Spare Destinations 1 8/3(2), 6/1*(2) A 3 1pt 6pt, 3pt, 1pt, 13pt [none] 2 10/5, 9/4, 6/1*(2) a 2 1pt 6pt, 8pt, 1pt, 13pt 5pt, 4pt 3 10/5, 8/3, 6/1*(2) A 2 1pt 6pt, 8pt, 1pt, 13pt 5pt, 3pt 4 9/4, 8/3, 6/1*(2) a 2 1pt 6pt, 8pt, 1pt, 13pt 4pt, 3pt Algorithm for the Hit Convention
Follow these steps to compare two plays in the same Nactation family, and determine which, if either, ranks higher under the Hit Convention.
 If neither play hits, then the Hit Convention is a tie.
 If either or both plays hit, then the one that results in the highest number of innerboard points ranks higher. This is true whether it hits or not.
 If both plays result in the same number of innerboard points, then the one that makes the most hits outranks the other. Double hits, for instance, always beat single hits.
 If both plays make the same number of hits, then the one that hits on the highest point wins.
 If the highest point is a tie, then check the second highest point where a hit is made. And so on.
 If all the hits in the two plays occur on the same points, then the Hit Convention results in a tie.
Step 2 above is what determines the ranking of A = 8/5(2), 6/1*(2).
Mike

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