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Nactation Algorithm for the Hit Convention

Posted By: Taper_Mike
Date: Thursday, 13 November 2014, at 5:41 a.m.

In Response To: Nactation help (David Rockwell)





White is Player 2

score: 0
pip: 156
9 point match
pip: 160
score: 1

Blue is Player 1
XGID=-a----E-CAA-fC---c-e----B-:0:0:1:55:1:0:0:9:10
Blue to play 55

eXtreme Gammon Version: 2.10

43D-65R-55

Attack Family
Rank Traditional Notation Nactation Inside Points Hits Owned Points Blot & Spare Destinations
1 8/3(2), 6/1*(2) A 3 1pt 6pt, 3pt, 1pt, 13pt [none]
2 10/5, 9/4, 6/1*(2) a 2 1pt 6pt, 8pt, 1pt, 13pt 5pt, 4pt
3 10/5, 8/3, 6/1*(2) A 2 1pt 6pt, 8pt, 1pt, 13pt 5pt, 3pt
4 9/4, 8/3, 6/1*(2) a 2 1pt 6pt, 8pt, 1pt, 13pt 4pt, 3pt

Algorithm for the Hit Convention

Follow these steps to compare two plays in the same Nactation family, and determine which, if either, ranks higher under the Hit Convention.
  1. If neither play hits, then the Hit Convention is a tie.
  2. If either or both plays hit, then the one that results in the highest number of inner-board points ranks higher. This is true whether it hits or not.
  3. If both plays result in the same number of inner-board points, then the one that makes the most hits outranks the other. Double hits, for instance, always beat single hits.
  4. If both plays make the same number of hits, then the one that hits on the highest point wins.
  5. If the highest point is a tie, then check the second highest point where a hit is made. And so on.
  6. If all the hits in the two plays occur on the same points, then the Hit Convention results in a tie.

Step 2 above is what determines the ranking of A = 8/5(2), 6/1*(2).

Mike

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