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Fun new probability puzzle

Posted By: HOMINID
Date: Saturday, 27 May 2017, at 9:05 p.m.

In Response To: Fun new probability puzzle (Jeremy Bagai)

This is all about roll odds init? I can do this in my head I think .lol lets calculate the survival chances

Gun A 2 bullets survival is 4/6 =24/36 =67% (you can multiply %'s) Two independant shots =67 x67= 46% or thereabouts

the two gun choice

Gun B 3 bullets =3/6=18/36 = 50% Two independant shots 50 x 50=25%

Gun C 1 bullet = 5/6=25/36 =70%

this is akin toblack and white balls 25+70=95 we want to draw the one bullet gun 70/95= 70% plus

pick one of the two revolvers

I can convert the fractions to % in my head because its BG stuff, but is my probability theory correct. I am sure someone will tell me lol

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