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OT: How to estimate a and p in E=aB+pB from multiple observations of E and B?

Posted By: Nack Ballard
Date: Wednesday, 21 December 2011, at 8:29 p.m.

In Response To: OT: How to estimate a and p in E=aB+pB from multiple observations of E and B? (Casper van der Tak)

Basically you are try to econometrically estimate the parameters in E = B, and hence, there are no parameters to estimate.

Perhaps an econometrical proof would be difficult but there's an easier way. An evaluation is a kind of estimation, and XG's 4-ply evaluation of the 62S-32T-33-d position shown below is [B=E].





White is Player 2

score: 0
pip: 162
2 point match
Crawford
pip: 159
score: 1

Blue is Player 1
XGID=-b----E-C--AdD---dAe----A-:0:0:1:33:1:0:1:2:10
Blue to play 33

1.4-ply24/18 13/10(2)eq: +0.074
Player:
Opponent:
61.47% (G:16.29% B:0.63%)
38.53% (G:7.75% B:0.23%)
2.4-ply24/18 6/3(2)eq: +0.074 (0.000)
Player:
Opponent:
61.31% (G:16.72% B:0.60%)
38.69% (G:7.59% B:0.21%)

eXtreme Gammon Version: 2.01, MET: Kazaross XG2

Nack

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