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win probability for a PR difference and match length

Posted By: Jason Lee
Date: Friday, 21 September 2012, at 2:33 a.m.

In Response To: win probability for a PR difference and match length (Joe Russell)

Joe: I am not sure I understand what you are saying. Are you saying if A is 5 to 1 to beat B and B is 2 to 1 to beat C, then A's chances are (5*2= 10) to 1 to beat C. I would have though C's chances would ~1/6*1/3

Joe is right, the misunderstanding comes into play by misinterpreting x-to-1 as a probability of 1/x, when it is actually 1/(x+1).

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