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63R-62$-44 and Nactation question

Posted By: Taper_Mike
Date: Thursday, 26 June 2014, at 1:29 p.m.

In Response To: 63R-62$-44 and Nactation question (Igor)





White is Player 2

score: 0
pip: 159
Unlimited Game
Jacoby Beaver
pip: 158
score: 0

Blue is Player 1
XGID=-b----E-C---dE-A-c-ea---A-:0:0:1:44:0:0:3:0:10
Blue to play 44

For a roll of doublets, the Z family is defined as follows.

  • One die is played on the far side of the board, including entering a checker from the bar.
  • Three dice are played down (i.e., to or within the outer board).

If there is more than one member in the Z family, use the Hit-More-6 rule to to rank them. See the Nactation Tutorial or my post Clarifying S (Split), Z (Reverse split), and B (Both) for more information and examples.

In the position 63R-62$-44, the Z family has two members. The first three die movements are the same in both plays: 24/20*, 13/9(2). The fourth die is the decider: 15/11 beats 13/9 by the wrinkle in the 6pt Convention. In the outer board, landing a spare on the 11pt outranks landing on the 9pt.

Z = 24/20*, 15/11, 13/9(2)
z = 24/20*, 13/9(3)

There is no reason to get fancy with this. I would play Z in this position.

Mike

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