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Aladdin and the Lethal Liquid

Posted By: Mike Clapsadle
Date: Tuesday, 7 May 2019, at 11:45 p.m.

In Response To: Aladdin and the Lethal Liquid (Nack Ballard)

2 solutions, but I'm assuming one is what you're looking for and the other is not.

Have one prisoner drink a sip from every other wine. Then have the second prisoner drink from the first two, skip the second two, and repeat. The third prisoner will drink from the first four, skip the next four...repeat. The fourth prisoner will do the same alternating with eight wines, then the fifth prisoner will alternate with 16 wines, and the sixth prisoner will drink from the first 32 wines and skip the last 32 wines. After you see which prisoners die, you can tell which wine killed them. You can either document each wine that they drank (there will be a unique combination for each wine), or you label the wines 0-63 instead of 1-64 and assigne a 0 to each prisoner that died, a 1 to each prisoner that lived, and this binary number will tell you which wine was poisoned. (you will need to do it starting with prisoner 6 first and proceed to 1). There's exactly one solution where all prisoners die, and one solution where they all live.

The other solution is just to give each prisoner a different wine, then an hour later give them each another. Do this for 10 hours and then when one dies, you should be able to figure out which wine killed him. This however only works if they die precisely in 24 hours after consuming the wine.

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