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Position of the Day 02-28-24 - All options cube

Posted By: rambiz
Date: Wednesday, 6 March 2024, at 2:22 p.m.

In Response To: Position of the Day 02-28-24 - All options cube (John O'Hagan)

We consider three scenarios:

1. First roll you roll a 61 and jump out. Probability is 2/36
2. First roll you roll a 1 but not 61. Probability is 9/36 and the average number of rolls to jump out from the edge is 36/11
3. First roll you do not roll a 1 at all and start over. Probability is 25/36

Considering the above the average number of rolls can be calculated as:

E=2/36*1+9/36*(1+36/11)+25/36*(1+E). Solving for E yields: E=720/121

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