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My best probability puzzle

Posted By: Timothy Chow
Date: Friday, 23 August 2024, at 4:30 a.m.

In Response To: My best probability puzzle (Bob Koca)

The case that I've analyzed in detail is a rectangle with m rows each of length m2, and in that case Andrew has an advantage if and only if the number n of prizes satisfies 2 ≤ n ≤ m3 – 2m + 1. Something similar is true for arbitrary non-square rectangles but I can't immediately tell you what the range is for a 3x5 rectangle.

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