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A backgammon problem (for a change)

Posted By: David Rockwell
Date: Sunday, 19 October 2008, at 7:36 p.m.

In Response To: A backgammon problem (for a change) (Chuck Bower)

The perfectly efficient bear-in sequence will include at least three aces and enough other pips to get off on time. In the absence of these numbers, second best would include at least one deuce played 7-5 wasting only one pip. The efficient bear-in appears very unlikely. So, waste one pip now with 7-5.

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