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BGonline.org Forums
A backgammon problem (for a change)
Posted By: David Rockwell In Response To: A backgammon problem (for a change) (Chuck Bower)
Date: Sunday, 19 October 2008, at 7:36 p.m.
The perfectly efficient bear-in sequence will include at least three aces and enough other pips to get off on time. In the absence of these numbers, second best would include at least one deuce played 7-5 wasting only one pip. The efficient bear-in appears very unlikely. So, waste one pip now with 7-5.
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