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Calculating the best/worst scenario in a race

Posted By: Rich Munitz
Date: Friday, 8 May 2009, at 5:53 p.m.

In Response To: Calculating the best/worst scenario in a race (Matt Reklaitis)

MR: "I think you need to add a tweak to account that no pips are wasted for a checker on the ace when there is also a checker on the deuce."

Why would it waste pips? The checker on the deuce point earns 1 half-roll, the checker on the ace gets another half roll. Total is 1 roll.

Lets say theres a checker on the ace and the deuce.

pipcount = p = 3 checkers on ace = a = 1

h = p-a / 1.5 = 3-1/1.5 = 2/1.5 = 1.33 -> 1 (round to nearest integer)

rolls = a+h /2 = 1+1/2 = 1

Perhaps if you gave an example of a position where the formula fails?

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