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A fair spot for the undefeated player

Posted By: Sam Pottle
Date: Tuesday, 16 June 2009, at 7:14 p.m.

In Response To: A fair spot for the undefeated player (Rich Munitz)

I'm not sure exactly what you're trying to count here. Assuming equal players, the probability of any given player becoming the undefeated finalist is 1/64 (or 1.5625%), as you said. The probability of any given player becoming the other (once-defeated) finalist is also exactly 1/64. Right?

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