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Probability Problem

Posted By: Gregg Cattanach
Date: Thursday, 27 August 2009, at 3:49 p.m.

In Response To: Probability Problem (poseidon)

I'm not sure what Stick's 'overcomplicating' comment means, however...

I count only 28 possible combinations, (AS+AH is the same as AH+AS).

6 contain 2 aces, 6 contain zero aces, 16 contain AK. If we know that one is an ace, then 6/22 (or 3/11) chance both are aces. There are 7 hands that contain the aces of spades; only three of them are A+A. 3/7 chance both are aces.

Misja got the same answer, but counted the number of hands twice.

I'm very curious why this result is controversial.

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