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Probability Problem

Posted By: joe freedman
Date: Thursday, 27 August 2009, at 6:35 p.m.

In Response To: Probability Problem (poseidon)

I can see why this is controversial. Let's assume the instructions are: "look at both of your cards, and tell me if at least one is an ace."

So if the subject says yes, I have at least one ace, then the odds of her having another ace are 3/11. Fine.

But what if you then ask the subject, which suit is the ace? Obviously, the ace has to be one of 4 suits. I seehow the calculation now yields 3/7. But how can her reply, which is basically forced (she has to identify a suit), increase the odds from 3/11 to 3/7?

Messages In This Thread

• Probability Problem
  poseidon -- Thursday, 27 August 2009, at 1:26 p.m.
  • Probability Problem
    misja -- Thursday, 27 August 2009, at 1:42 p.m.
    • Probability Problem
      Stick -- Thursday, 27 August 2009, at 3:31 p.m.
    • Probability Problem
      Petter Bengtsson -- Thursday, 27 August 2009, at 3:46 p.m.
  • Probability Problem
    Gregg Cattanach -- Thursday, 27 August 2009, at 3:49 p.m.
    • Probability Problem
      Bob Koca -- Thursday, 27 August 2009, at 4:19 p.m.
    • Probability Problem
      Chuck Bower -- Thursday, 27 August 2009, at 4:46 p.m.
    • Probability Problem
      Jason Lee -- Thursday, 27 August 2009, at 7:54 p.m.
  • Probability Problem
    Neil Robins -- Thursday, 27 August 2009, at 4:14 p.m.
    • Probability Problem
      Gregg Cattanach -- Thursday, 27 August 2009, at 5:37 p.m.
      • Probability Problem
        Bob Koca -- Thursday, 27 August 2009, at 5:56 p.m.
        • Probability Problem
          Gregg Cattanach -- Thursday, 27 August 2009, at 6:07 p.m.
          • Probability Problem
            Bob Koca -- Thursday, 27 August 2009, at 7:42 p.m.
            • Probability Problem
              Gregg Cattanach -- Thursday, 27 August 2009, at 8:09 p.m.
              • Probability Problem
                joe freedman -- Thursday, 27 August 2009, at 8:26 p.m.
                • Probability Problem
                  poseidon -- Thursday, 27 August 2009, at 8:37 p.m.
                • Probability Problem
                  Jason Lee -- Thursday, 27 August 2009, at 8:47 p.m.
              • Probability Problem
                Gregg Cattanach -- Friday, 28 August 2009, at 1:58 a.m.
                • Probability Problem
                  Paul Vianna -- Friday, 28 August 2009, at 2:11 a.m.
                  • Probability Problem
                    Chuck Bower -- Friday, 28 August 2009, at 4:06 p.m.
            • monte hall called this
              garyo -- Saturday, 29 August 2009, at 7:51 a.m.
  • Probability Problem
    Chuck Bower -- Thursday, 27 August 2009, at 5:16 p.m.
  • Probability Problem
    Timothy Chow -- Thursday, 27 August 2009, at 6:03 p.m.
    • Probability Problem
      Bob Koca -- Thursday, 27 August 2009, at 6:06 p.m.
      • Probability Problem
        poseidon -- Thursday, 27 August 2009, at 6:18 p.m.
  • Probability Problem
    joe freedman -- Thursday, 27 August 2009, at 6:35 p.m.
    • Probability Problem
      joe freedman -- Thursday, 27 August 2009, at 6:39 p.m.
  • Probability Problem
    Jason Lee -- Thursday, 27 August 2009, at 7:57 p.m.
  • Probability Problem
    Bob Koca -- Friday, 28 August 2009, at 2:13 a.m.
    • Probability Problem
      poseidon -- Friday, 28 August 2009, at 10:29 a.m.