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21 RO at dmp

Posted By: Nack Ballard
Date: Saturday, 5 February 2011, at 2:34 a.m.

In Response To: 21 RO at dmp (Ian Shaw)

2 * 36^3 is a lot of trials. But what if one of the 2nd roll responses is being played incorrectly? Wouldn't we gain more information by rolling out 21$ and 21D 23^2 times and combining the results.

Do you mean 21$ and 21S? ("21D" means 13/10.)

Why 23^2 = 529 trials?

For purposes of discussion, suppose 21$-11 is misplayed. Why would we gain more information by rolling out two single plays individually and then combining the data? (We'll ignore for the moment that the arithmetic would be a hassle.)

Nack

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