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Midpoint and 7pt: relationship

Posted By: Nack Ballard
Date: Thursday, 24 March 2011, at 8:06 p.m.

In Response To: Striping the midpoint (mtuhtan)

Nack (previous): "It is often right to strip the decreased-value midpoint after making the 7pt."

Can you please elaborate this little more and/or show some positions where this applies? This is the first time I hear about this and would like to know more.


For situations like these, real-position pair examples are elusive, because a change in distribution or race can have a major effect.

The feature position (61P-55P-62) is on the left (below). For comparison, an artificial position has been created on the right. There, Blue has played a 4 down and a 1 backwards (underlined) instead of 6 down and 1 forwards. The positions are distributionally similar, but there is a difference of 6 pips in the race (4 pips in the position plus 2 pips in the roll).

Using Snowie eval as arbiter, D (Down) beats S (Split-and-down) by .150 on the left, whereas D beats S by only .082 on the right. Granted, it is a bit more dangerous to split to the 18pt than the 20pt, and a spare on the 7pt is a bit more synergetic than a spare on the 9pt, factors that favor D on the left, but against that the race/timing difference of 6 pips should favor D about as much on the right. If we assume all that roughly washes, the difference in margins of .068 is telling.

147


2O '2X ' '5X '3X ' ' '4O

2X ' ' ' '5O2O2O ' ' '3X

61P-55P-62160


147


2O '2X ' '5X '3X ' ' '4O

2X ' ' ' '5O '2O2O ' '3X

41P-55P-42164


Below is the same position pair except White owns her 5pt instead of her 3pt. This time we'll compare D (Down) to Z (reverse split with the 2 and down with the larger number).

On the left, D beats Z by .030. On the right, D beats Z by only .017. The number that splits is identical this time: that factor is taken out of the equation. And yet D beats Z by more on the left in spite of the 6 pips difference in race/timing.

151


2O ' ' '2X5X '3X ' ' '4O

2X ' ' ' '5O2O2O ' ' '3X

61P-44P-62160


151


2O ' ' '2X5X '3X ' ' '4O

2X ' ' ' '5O '2O2O ' '3X

41P-44P-42164


The opponent is often looking to split to your 7pt (especially as a deflection ploy if you still have five checkers on your 6pt you want to unload onto your 5pt or 4pt) and you will then want at least one 6 to hit or point-on-head without breaking your midpoint, and possibly more 6s in case a hitting exchange ensues on the 7pt. The key, then, is that after you have made your 7pt, you no longer care so much if you have few or no spares on your midpoint.

Also, the midpoint and 7pt are inefficiently placed six points apart. You don't mind as much giving one or the other up as you would if they were not six apart. Ultimately, if you break your midpoint and end up with the 11pt, 10pt and/or 9pt instead, it/they will work together with the 7pt as part of the same prime. If, OTOH, you break your midpoint and don't own your 7pt, you'll have a nagging hole on your 7pt through which your opponent can escape, with nobody on the midpoint to act as a proper halfback.

Nack

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