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Alternative to byes

Posted By: Bob Koca
Date: Sunday, 1 May 2011, at 8:26 p.m.

In Response To: Alternative to byes (Chuck Bower)

"2^(n+1) < N < 2^n. Play a round robin and eliminate N - 2^n [or even N - 2^(n-1)] "

And deal with tie breaks to make it work? Explain more about exactly how you would be eliminating that amount.

" The length of the RR increases m/l linearly"

What does m/l linearly mean? The number of games needed is n(n-1)/2 so it increases faster than linearly.

"You could truncate the RR before every pairing is completed, but for a field of players with significant discrepancies in skill level, that seems to throw more 'luck of the draw' back into the mix. "

Or you could just play Swiss.

"N=6. Five rounds of Round-Robin eliminates either one or three; then one or two rounds of knockout find the winner."

So you have then 3 or 5 players left?

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