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3-Dice Probability Question

Posted By: Ray Kershaw
Date: Sunday, 8 May 2011, at 12:31 a.m.

In Response To: 3-Dice Probability Question (Brett Meyer)

Correct. There are 120 ways that the three dice are different: any one of 6 numbers for the first, times any one of 5 numbers for the second, times any one of 4 numbers for the third. There are 6 ways that the three dice are the same. That leaves 216 - 120 - 6 = 90 ways that any two of the dice are the same and the other is different.

Alternatively: any two of the dice can contain the double (3 ways); that double can be any one of six numbers (6 ways); the third dice can be any one of the five remaining numbers (5 ways). And 3 x 6 x 5 = 90.

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