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OT: Trigonometry Problem

Posted By: Ryan McKinnon
Date: Thursday, 9 June 2011, at 10:54 p.m.

In Response To: OT: Trigonometry Problem (Ian Shaw)

Pythagorean theorem says that DC = sqrt(5^2+8^2) = sqrt(89), DB = sqrt(5^2+10^2) = sqrt(125), and BC = sqrt(8^2+10^2) = sqrt(164).

Law of cosines says that BC^2 = DC^2 + DB^2 - 2*DC*DB*cos(angle BDC), so solving for cos(angle BDC), we get cos(angle BDC) = 0.2370, so angle BDC = 76.3 degrees.

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