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Thanks Jason ** Question answered **
Posted By: Jason Lee
Date: Thursday, 29 January 2015, at 8:52 p.m.
In Response To: Thanks Jason ** Question answered ** (John McDonald)
If I am doing this correctly, then p +/ Square root [(1/n)*p*(1p)] for a 95% CI
You're close. 95% CI requires a zscore of 2, so your CI should be p ± 2 sqrt(...)
Technically, the 2 is more like 1.96, but everybody just uses 2.
JLee

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