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Naccel 2 -- post #4

Posted By: Nack Ballard
Date: Wednesday, 13 January 2010, at 2:20 a.m.

Good news: Matt Ryder has managed to create a diagram with Naccel point-numbering! (I see in another post that Ian was smart enough to reproduce it, but I confess I need additional help doing the same.) I hope to have Naccel point-numbering in my next post.

In the meantime, at least the current diagrams (starting with post #3) are viewable with all browsers (not just with Windows Internet Explorer) and, also thanks to Matt's instructions, I have now removed all distracting checkers in the bearoff tray when I illustrate counting components of a position.

This is post #4 of the Naccel 2 series. If you would like to review or get caught up, here are post #1, post #2 and post #3.

For this post (#4), Lucky Jim submitted two positions.

You know about reflections on the near side. (If not, click on "post #1" above and see the fourth and fifth diagrams.) Cancellations around S0 (trad 6pt) count zero, which means there are a lot of checkers you don't have to count at all.

There are also reflections on the far side. Because they reflect around S2 (Opp's bar point) instead of S0, they count 2 per checker -- that is, count the number of checkers you see and double it.

With the midpoint featured, this is the most commonly arising far-side reflection:

Far-side reflection	8

Doubling the number of checkers, 4, gives us a count of 8. (If these were blots instead of points, the count would be only twice 2 = 4.)

Let's apply that knowledge to the Blue side of Jim's first position:

	3(3)
	17(2)

Blue's checkers on the near side cancel out except for the n2 checker (which counts 2 pips). So...

8 (reflection), plus 9 for S3, plus n2, gives a count of 17(2).

[Jim and Ian counted similarly, except they didn't yet know of the far-side reflection. Instead, they shifted to S3 and S1, which is fine but it adds a step of visualization.]

White's count is even easier (as Jim and Ian found as well), so I won't spend a new diagram. Her entire near side goes poof (reflection/cancellation around n0), so the entire count is 3(3).

The midpoint is nice for leftover counts because it's trivial to multiply 1(1) for each checker, and if it has as many as six checkers it just counts 7.

In short, the count is 17(2) to 3(3), a difference of about 14 supes (super-pips). [Round supes (which can be thought of as crossovers) are a good way to assess Blue's timing. As 12 of the 14 supes are accounted for in bringing home the vital-to-keep anchors, that only leaves 2 spare supes, which are roughly offset when White's 6s then 5s are killed bearing in later. And the S3 spare might not escape and get its 3 supes. Yikes, looks like a monster pass.]

Here is Jim's second position. There are many ways to count, but I'll give you one that works well with what you know so far.

For Blue, try this easy mental shift:

	8(1)

Now, here's the trick that you need: Conjure a new checker on n0. Remember, n0 is not only a black hole but also a white hole: even when n0 looks vacant, phantom checkers always exist there for your convenience. Now, LIFT that conjured n0 checker onto n-1, which is a 1-pip adjustment.

So, your count: Four on S3 counts 12, six-sym (around n-3) is -3, the stack is -1, and add the 1-pip lift needed to get the stack. That's a net of 8(1).

Now let's count White. Her position again is... Try this mental shift (2 pips forward, 2 pips back):

	-4(-3)

The stack is -3, the six-sym (three-prime) is -1, and the three spares on n-1 are -3 pips. Total of -4(-3). In case you want to convert, -4*6 -3 +90 = 63.

Do you see a similarity with what you did in Blue's inner board and in White's inner board? Six-stacks, and six-syms (which are often three-primes), are powerful weapons.

When both Blue and White checkers are home, cluster-counting is relatively at its best. With only one quadrant to count, Naccel's edge disappears. But if you want to become lightning fast, it pays to practice counting all positions with Naccel (instead of lazily falling back), even though at first it may be slow and even confusing in certain situations. That's to be expected -- you're still tying your skate-laces at this point.

Finally, I promised to show you the way I counted Blue (noting that the alternative method suggested above is perfectly legit). To follow my count, you'll need two key pieces of information.

First, let's review the "mirror." It was introduced here (third and fourth diagrams). Below is another example:

Mirror	4

For a regular mirror, the near-side point is (as you can see) a pip visually closer to the bear-off tray (than the far-side point would be if it were dropped straight down). The number of checkers = 4, and thus the count = 4.

For advanced anchors (or blots), you can often use regular mirrors to offset checkers in the home board. But for deep anchors, you will tend to use "zag-mirrors" (or "zags" for short).

Starting with the mirrored point shown above (count of 4), if you zag (move) back either point back 3 pips, you increase the count by 6 pips or 1 supe, to a count of 5, and you have yourself a zag mirror.

If it is the far-side point that is zagged, we get the zag mirror shown below.

Zag Mirror	5

Whereas with regular mirrors, the near-side point is 1 pip closer to the bearoff tray; with zag mirrors, the near-side point is 2 pips further away.

As stated, zag-mirrors count 5. The occupied points are opposite colors, which helps remind you that the count is odd.

Now for the second part of the explanation:

A triplet (three-stack), which was introduced here (see seventh diagram), is a basic squad (i.e., a group of checkers within a quadrant field). An example is shown below.

Triplet	-1

You count a triplet by dividing the number of the point on which it resides by 2. This triplet is on n-2, so the count is -1.

The triplet has a variant squad, which can be obtained by moving two of the checkers 1 pip towards the nearest Super, and the third checker 2 pips in the other direction, to compensate. It looks like this:

Wedge	-1

This squad is called a "wedge" (it is shaped like a door wedge). To count a wedge, take the point number that is in between the blot and point but closer to the latter (or just shift to it, thereby reenacting a triplet on the appropriate point, if you need the visual help), and divide it by 2.

Here, the in-between point is n-2. Dividing by 2 gives you wedge's count of -1.

You can also double the height of the wedge which gives you a "double wedge," and this also-commonly seen formation counts the same as the in-between point number (e.g., if you double the height of the wedge shown above, the count is -2). Both the wedge and the double wedge can be great counting tools.

Now that you know what a zag (zag mirror) and a wedge are (or if you don't remember, then review), I'll show you how I counted Blue in Jim's position, repeated below.

To count Blue, all I did was to move one pip forward, from n0 to n-1, and sum the count of two formations:

Double Zag	10

Double Wedge	-2

That's 10 for the double zag, -2 for the double wedge, plus the 1-pip lift: my count is 8(1).

The checker left on n0, is, as usual, invisible.

Next position?

Nack

Messages In This Thread

• Naccel 2 -- post #4
  Nack Ballard -- Wednesday, 13 January 2010, at 2:20 a.m.
  • Naccel 2 -- post #4 - 2 new positions
    Lucky Jim -- Wednesday, 13 January 2010, at 10:27 p.m.
    • Naccel 2 -- post #4 - 2 new positions
      Ian Shaw -- Thursday, 14 January 2010, at 12:18 p.m.
    • Naccel 2 -- post #4 - 2 new positions
      Nack Ballard -- Saturday, 16 January 2010, at 5:15 a.m.
      • Naccel 2 -- post #4 - 2 new positions
        Lucky Jim -- Sunday, 17 January 2010, at 10:10 p.m.
  • Naccel 2 -- post #4
    Ian Shaw -- Thursday, 14 January 2010, at 11:13 a.m.
    • Naccel 2 -- post #4
      Ian Shaw -- Thursday, 14 January 2010, at 9:22 p.m.