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BGonline.org Forums
Average number of rolls to roll 66
Posted By: Bob Koca In Response To: Average number of rolls to roll 66 (Raj Jansari)
Date: Tuesday, 6 September 2011, at 11:06 a.m.
Here is another way.
Consider what happens on the first roll. If the event occurs then you are done after one trial. If it does not then you have used up one trial and then it is like starting over again. So if E is the expected number of tosses needed and p is the probability of success we have that
E = (p)(1) + (1-p) (1+E)
Solving for E gives E = 1/p.
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