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Average number of rolls to roll 66

Posted By: Ray Kershaw
Date: Tuesday, 6 September 2011, at 12:44 p.m.

In Response To: Average number of rolls to roll 66 (Raj Jansari)

In a large number of rolls, n, and with probability of success on a single roll, p:

average rolls = total rolls / total successes = n / np = 1 / p

p = 1/2 (coin): average = 2 p = 11/36 (enter five point board): average = 36/11 = 3 and a bit p = 1/36 (double 6s): average = 36.

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