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BGonline.org Forums
Average number of rolls to roll 66
Posted By: Ray Kershaw In Response To: Average number of rolls to roll 66 (leobueno)
Date: Wednesday, 7 September 2011, at 9:15 a.m.
Correct. You solve using logarithms.
(1-p)^n = 0.5
n * log(1-p) = log (0.5)
n = log (0.5) / log(1-p)
n = 24.6 when p = 1/36
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