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some clarifications

Posted By: Chuck Bower
Date: Friday, 16 December 2011, at 3:27 a.m.

In Response To: some clarifications (Timothy Chow)

I don't play bridge and have only an approximate understanding of the rules, but does your question boil down to the following? A and B have 13 cards each, drawn from the same deck of cards. Among these 26 cards, there are exactly two aces, but apart from this condition, all possible pairs of hands are equally likely.

We now randomly choose one of A's cards, and randomly choose one of B's cards, and expose them. It so happens that A's card is an ace and B's is not.

What is the probability that the other ace is in A's hand?

This isn't quite it but you might be on the right track. See (all of) Xavier's posts, although I'm not quite sure I agree with him (yet).

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