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Introducing Chuck's Rule of 0.7868 :)

Posted By: Chuck Bower
Date: Saturday, 29 December 2012, at 7:57 p.m.

In Response To: Introducing Neil's Rule of .6 (neilkaz)

Re: formulas...I've tried to work out something for 2 away scores, but haven't been happy with it. One of these days..I'll work harder on it.

Take any 2-away, n-away score you know (best if n is at least 6, though) and multiply by 0.7868 to get the n+1 score. But unless you've been trained by Art Benjamin it's going to be tough to do 4 decimal place multiplications in your head.

It is interesting that these MEQ's are very nicely exponential. (Put values on a semilog plot -- or just do XY-plot in excel double click the vertical axis and checkmark the "logarithmic scale" box.)

I suspect there is a shortcut that's easier than multiplying by 0.7868. I'll play around a bit more.

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