| |
BGonline.org Forums
Criss-Cross Count
Posted By: Michael In Response To: Criss-Cross Count (Nack Ballard)
Date: Wednesday, 26 September 2018, at 11:35 a.m.
I was impressed by your reply and decided that I should go on and try to learn this method.
For a start let me express my deepest appreciation for the time you spent and the hard work you did
in trying to explain this method in this forum (whose HTML support is only limited to images already saved on other servers.)
Combining your explanation and Max's I easily understood steps 1 and 2.
Then proceedded to step 3 and got puzzled because of the absense of any definition of symmetry.
At first I thought it was along a horizontal exis....
Anyway I am going to explain how I finally got it, just in case others would wonder:
I am almost certain I got it right-please correct me if I am wrong.
At step 3 he divide the board in 8 quadrants.
1st quadrant contains points 1-3, 2nd contains points 4-6, and the 8th points 22-24.
The axis of symmetry of each quadrant is vertical along the central point.
So we end up to 8 axes of symmetry, one along the 2point, another along the 5 point, etc etc and final one is along the 23 point.
The checkers on the axes of symmetry don't matter. What matters are the checkers on the left and right points of each axis.
So considering the first quadrant (points 1,2 and 3) the axis is vertical along the 2 point and what matters
are the number of checkers at the 1 and 3 points. We remove (or rather encircle) checkers so that whatever
number of checkers exists on the 3 point is the same as the number of checkers on the ace point and vice versa.
We do the same for all 8 quadrants.
However after this point I got struck again as I don't understand the criteria to put a plus or minus sign on the circles.
Looking at Max's examples 1 and 2, at example 1 he's put a - sign on the encircled checker in first quadrant,
however in example 2 he's put a + sign. I don't get it.
Could you or Max please explain?
| |
BGonline.org Forums is maintained by Stick with WebBBS 5.12.