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Naccel 2 -- post #4 - 2 new positions

Posted By: Lucky Jim
Date: Wednesday, 13 January 2010, at 10:27 p.m.

In Response To: Naccel 2 -- post #4 (Nack Ballard)

I have posted a further couple of positions below – again they are ones just picked from a backgammon newsletter –

Position 1
Match to 7, Tied at 0-0
Blue on roll. Cube action?
White125

Blue115
Position Id: 1uwGATC2bSEYQA
Match Id: cAngAAAAAAAA

With this position the approach I took was as follows:

Blue

For counting purposes the man on the bar needs to go on the 24 point so that is one pip forward to the 24 point for a count of 3 (1).

I moved the man on the blue 7 point 4 pips backwards to go on top of the checker on the eleven point so as to create a zag for 5 (-4)

This means we are running with a net (-3 pips)

The six-sym around n-3 gives a count of -3

There are two pips to move back from the n-1 point to the n0 point so add those to the existing -3 pips gives a total of -5 pips

This gives 3 + 5 -3 = 5 and – 5pips.

5 is the same as 4(6) so 4(6) less 5 pips is 4(1)

Naccel count for Blue is 4(1)

White

Two men on the white 24 point gives a count of 6

Move the checker from the 12 point to the 13 point for a count of 1(1)

The checkers on the white 4 and 8 points cancel each other out

If we move the checker forward one pip from the 3 point to the 2 point then we have a triplet on n-4 so that gives a count of -2. (plus 1 more pip)

This leave a final 3 checkers on the 7 point to move to the 6 point. (3 more pips)

The count excluding pips is 6 + 1 – 2 = 5 and there are 5 pips to add so a Naccel count for white of 5 (5)

Position 2

Match to 7, Tied at 0-0
Blue on roll. Cube action?
White26

Blue62
Position Id: AQAA6rY7AQAAAA
Match Id: cAngAAAAAAAA

Blue

The six-sym around n-2 gives a count of -2

The triple on n-4 gives a count of -2

The checker on n-5 and the remaining checker on n-1 go back to n0 and the checker on the n2 goes forward to n0 for a net movement of pips of -4

All counters on n0 can be ignored

-2 + -2 = -4 and then include the pips for a Naccel count of -4(-4)

White

There is one on the bar that will need to go one pip forward to commence on the 24 point 3(1) and there is one on the n-5. However I am not sure how the counters which have been borne off are accounted for and so would appreciate a steer from Nack as to how you proceed here.

Regards Jim - (very slow skater)

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