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Puzzle

Posted By: Tom Keith
Date: Monday, 30 August 2010, at 5:48 p.m.

In Response To: Puzzle (Timothy Chow)

White could have 13 checkers on the 1 point and one checker each on the 3 and 5 points, with Black having two or more checkers on each of White's 2 and 4 points. The only way White will not be forced to bear a checker immediately is by rolling 42 and playing it 5/1 3/1, breaking contact.

That works!

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