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x + y Backgammon Puzzle -- Solution
Posted By: pierrez In Response To: x + y Backgammon Puzzle -- Solution (Nack Ballard)
Date: Friday, 3 September 2010, at 6:18 p.m.
Nack,
I misread your condition for white as "White never rolls smaller or equal than a deuce on either die" instead of smaller than.... In other words, condition for white is the complement of the condition for blue.
Here below are my solution with extra features:
all wins are bargammons same Blue starting position for minimum and maximum pipcount difference same sequence of dice for both sides in both configuration.
White wins a BG in 5 + 4 = 9 rolls 39
Blue wins a BG in 5 + 4 = 9 rolls 28
White wins a BG in 5 + 4 = 9 rolls 110
Blue wins a BG in 5 + 4 = 9 rolls 28 On the left, Blue on roll gets 11 two times bearing off 4 checkers, then 11 bearing off 1-1-2, then 22 bearing off 6 and 2, and 22 on his last roll (bearing off 4 and 4), bargammoning White who keeps fanning with 44.
On the left, White on roll gets 66 and plays Bar/19*/13/7/1. Blue rolls 11 repeatedly while White rolls 66 the rest of the game, winning a bargammon.
On the left, Blue on roll gets 11 two times bearing off 4 checkers, then 11 bearing off 1-1-2, then 22 bearing off 6 and 2, and 22 on his last roll (bearing off 4 and 4), bargammoning White who keeps fanning with 44.
On the right, White on roll gets 66 and plays Bar/19*/13/7/1. Blue rolls 11 repeatedly while White rolls 66 the rest of the game, winning a bargammon.
Pierre
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