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x + y Backgammon Puzzle -- Solution

Posted By: pierrez
Date: Friday, 3 September 2010, at 6:18 p.m.

In Response To: x + y Backgammon Puzzle -- Solution (Nack Ballard)

Nack,

I misread your condition for white as "White never rolls smaller or equal than a deuce on either die" instead of smaller than.... In other words, condition for white is the complement of the condition for blue.

Here below are my solution with extra features:

  • all wins are bargammons
  • same Blue starting position for minimum and maximum pipcount difference
  • same sequence of dice for both sides in both configuration.

    White wins a BG in 5 + 4 = 9 rolls39


    eX ' ' ' ' ' ' ' ' ' ' '

    aO2O '2O '1O ' ' ' ' ' '

    Blue wins a BG in 5 + 4 = 9 rolls28

    White wins a BG in 5 + 4 = 9 rolls110


    1X ' ' ' 'cX ' ' ' ' '1X

    aO2O '2O '1O ' ' ' ' ' '

    Blue wins a BG in 5 + 4 = 9 rolls28

    On the left, Blue on roll gets 11 two times bearing off 4 checkers, then 11 bearing off 1-1-2, then 22 bearing off 6 and 2, and 22 on his last roll (bearing off 4 and 4), bargammoning White who keeps fanning with 44.

    On the left, White on roll gets 66 and plays Bar/19*/13/7/1. Blue rolls 11 repeatedly while White rolls 66 the rest of the game, winning a bargammon.

    On the left, Blue on roll gets 11 two times bearing off 4 checkers, then 11 bearing off 1-1-2, then 22 bearing off 6 and 2, and 22 on his last roll (bearing off 4 and 4), bargammoning White who keeps fanning with 44.

    On the right, White on roll gets 66 and plays Bar/19*/13/7/1. Blue rolls 11 repeatedly while White rolls 66 the rest of the game, winning a bargammon.

    Pierre

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