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Cubeless matches?

Posted By: Frank Berger
Date: Tuesday, 25 May 2010, at 8:34 p.m.

In Response To: Cubeless matches? (Matt Cohn-Geier)

You're right. I checked my code, in calculating the MET the cube isn't involved at all, but in the Post Crawford table and so the influence creeps in....

ciao Frank

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