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Probability one play is best from RO of equal plays

Posted By: Maik Stiebler
Date: Friday, 24 November 2017, at 5:04 p.m.

In Response To: Probability one play is best from RO of equal plays (Bob Koca)

What I think XG does is

- d:= equity difference of play A and play B estimated from the rollout

- jsd:= joint standard deviation of equities of play A and play B estimated from the rollout

- output [Phi^(-1)](d/jsd), where Phi is the cumulative of the standard normal distribution (or similar Student's t-distribution, shouldn't matter for large enough N)

As d/jsd is approximately standard normal distributed (again, at least for large N), the output is approximately uniformly ]0,1[-distributed. I think.

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