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What is the lowest winning % for Too good?

Posted By: rambiz
Date: Thursday, 11 July 2013, at 3:13 p.m.

In Response To: What is the lowest winning % for Too good? (Rick Janowski)

I meant the cubeful equity. Twice, I haven't been too clear about that, as Bob Koca have also kindly warned me in this post.
The whole discussion helped me to grasp a few things better. My biggest misconception was the following:
I was thinking, we are solving a constrained optimization problem, with only 2 constraints:
a) The sum of probabilities of games won(single+gammon+backgammon) plus games lost(single+gammon+backgammon) is equal to one.
b) It is a too good to double position (whatever it means).
Now I know, that the 6-tuple (single win, gammons won, bg's won, single loss, gammons lost, backgammon lost) is also subject to other unknown constraints, like for example (as you have put forward): you can't win a lot of backgammons and lose some single games, without also winning a few single games. It is kind of obvious but I was not thinking of it, and that's the reason why, I mistakenly thought that, the real world answer of the question astonishingly lies outside the live-dead cube model intervals, and it was really confusing me.
Never mind. No one should prevent me from getting wiser.

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