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cubeless RO

Posted By: Bob Koca
Date: Tuesday, 16 July 2013, at 7:09 p.m.

In Response To: cubeless RO (Rick Janowski)

I think I used the values for DT from the cubeful RO instead. Using the cubeless numbers I get L = 1.879 as average size of loss and W = 1 as average size of win and then (L - .5)/(W + L + .7 * .5) = .427 agreeing with your calculation. That assumes an infinite number of possible recubes all at .7 efficieny right?

In a position like this one where the cubeless equity is high due to lots of bonus wins the taker's win percentage is closer to the needed cash point so the efficiency might be higher than say for a race. I don't see the volatility as being much different from a race but that is mostly a guess. Is having a neural net learn the right efficiencies to use a possible approach?

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