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Fixing the 80 player bracket (long)

Posted By: Tom Keith
Date: Thursday, 6 February 2014, at 1:56 p.m.

In Response To: Fixing the 80 player bracket (long) (Bob Koca)

Not quite right.

If there are 5 players in a single elimination then the two non-bye players get 1/(2N) = 1/10 of the prize pool.

But there are two complications here. The first is that the loser of the antibye game gets equity but from a different prize pool.

Here's how I think of it: There are effectively 20 shares of equity that will be distributed among the final five players -- the 16 shares of prize money that go to the four semifinalists, 2 extra shares (1/10 of 20) to the winner of the nonbye players, and the equivalent of 2 shares of equity that goes to the loser of the nonbye players as a semifinalist in the Consolation bracket.

Another is that if the bracket is not a full 80 then a player getting the antibye who had a bye in the first round should not get compensation.

It is probably better to treat compensation for first round non-byes separately. It keeps the calculations simpler and assures that all nonbye players are compensated appropriately (if you even want to go that route).

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